given NA values fill them with the next non-na value
fill_backward(x)
x | A numeric vector of values |
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Works very well in context of dplyr to carry out backwards imputation
fill_backward(c(1.0, NA, 2))#> [1] 1 2 2fill_backward(c(NA, 1, NA, 2))#> [1] 1 1 2 2library(dplyr) df <- data_frame(id = c(1, 1, 2, 2), obs = c(1.2, 4.8, 2.5, NA)) df %>% group_by(id) %>% mutate(obs_imp = fill_backward(obs))#> # A tibble: 4 x 3 #> # Groups: id [2] #> id obs obs_imp #> <dbl> <dbl> <dbl> #> 1 1 1.2 1.2 #> 2 1 4.8 4.8 #> 3 2 2.5 2.5 #> 4 2 NA NA